Math 7 · Unit 5: Angles and constructions · Cambridge Lower Secondary Maths Stage 7
5.1 A sum of 360°
20 questions · e.g. Angles around a point
Questions
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5. Question 2b: three angles around a point are 94°, 119° and b. Work out b.
Check6. Question 2c: four angles around a point are 85°, 65°, 95° and c. Work out c.
Check7. Question 3a: a quadrilateral has angles a, 110°, 80° and 110°. Calculate a.
Check8. Question 3b: a quadrilateral has angles 75°, 105°, 75° and b. Calculate b.
Check9. Question 4a: in diagram a, the angles on the line XY are 63° and 117°. Which statement is true?
- 63° + 117° = 360°, angles around a point.
- 63° + 117° = 180°, angles on a straight line.
- 117° is an obtuse angle, so XY is not a straight line.
- 63° + 117° = 190°, so XY is not a straight line.
10. Question 4b: in diagram b, the angles on the line XY are 132° and 48°. Which statement is true?
- 132° + 48° = 190°, so XY is not a straight line.
- 132° + 48° = 180°, angles on a straight line.
- 132° + 48° = 360°, angles around a point.
- 48° is an obtuse angle, so XY is not a straight line.
11. Question 4: give a reason why diagram c is the odd one out.
- Diagram c has the smallest angle.
- 124° is an obtuse angle.
- 54° + 124° = 180°, like the others.
- 54° + 124° = 178°, not 180°, so XY in c is not a straight line.
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13. Question 6a: calculate the value of a.
Check14. Question 6b: calculate the value of b.
Check15. Question 7: one angle of a parallelogram is 62°. Work out the size of the other three angles.
Check16. Question 8: calculate the value of x.
- x = 10°
- x = 350°
- x = 0°
- It cannot be done: 95° + 125° + 150° = 370°, which is more than 360°, so the diagram is impossible.
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